Asked by Joshua
When a force of 50N is applied to the free end of an elastic cord, an extension of 4cm is produced. Calculate the work done on the cord.
Answers
Answered by
Anonymous
F = 50 N
x = 4 cm = 0.04 m
F/x = k = 50/.04 = 1250 Newtons / meter
W = integral F dx = (1/2) k x^2
= (1/2) 1250 (.04)^2 = 1 Newton meter = 1 Joule
x = 4 cm = 0.04 m
F/x = k = 50/.04 = 1250 Newtons / meter
W = integral F dx = (1/2) k x^2
= (1/2) 1250 (.04)^2 = 1 Newton meter = 1 Joule
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.