Asked by Chris
                Find the slope of a line tangent to the curve y=2x^2+4x at the point P(−3,6) by finding the limit of the slopes of the secant lines PQ where Q has x-values −2.5, −2.9, −2.99, and −2.999. Sketch the curve and tangent line
            
            
        Answers
                    Answered by
            oobleck
            
    The secant from (-3,6) to (-2.5,2.5) has slope (2.5-6)/(-2.5+3) = -7
now do the same calculation for the other values.
    
now do the same calculation for the other values.
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