Asked by Jack
Sketch a graph of a fifth-degree polynomial f(x) such that f(x) < 0 when x< -2 or 4 < x < 7, and f(x)>0 when -2<x<0, 0<x<4 or when x>7. What conclusions can you make about the sign of the leading coefficient and its end behaviour (the sign changes the direction of the graph)? Explain your answer using terminology.
Answers
Answered by
oobleck
Since f(x) is neither positive nor negative at x=0, that makes 0 a double root.
f(x) = x^2(x+2)(x-4)(x-7)
see the graph at
https://www.wolframalpha.com/input/?i=x%5E2%28x%2B2%29%28x-4%29%28x-7%29
f(x) = x^2(x+2)(x-4)(x-7)
see the graph at
https://www.wolframalpha.com/input/?i=x%5E2%28x%2B2%29%28x-4%29%28x-7%29
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