Asked by Anonymous
A piece of wire 40cm is bent to form aright-angle triangle whose hypotenuse is 17cm long.Find the lengths of two sides of the triangle
Answers
Answered by
oobleck
The other two sides have a total length of 40-17 = 23, so if one side is x cm, then
x^2 + (23-x)^2 = 17^2
now finish it off.
By the way, you could save some calculation if you learned a few of the basic Pythagorean triples.
x^2 + (23-x)^2 = 17^2
now finish it off.
By the way, you could save some calculation if you learned a few of the basic Pythagorean triples.
Answered by
Vivian Asasira
Please finish it
Answered by
Vivian Asasira
Hurry
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