Question
A 6.8 g bullet traveling at 395 m/s goes through a stationary block of wood in
4.3 x 10-4 s and emerges at 102 m/s. How thick is the wood?
How do I calculate the thickness of the block of wood?
4.3 x 10-4 s and emerges at 102 m/s. How thick is the wood?
How do I calculate the thickness of the block of wood?
Answers
R_scott
the assumption is uniform acceleration (deceleration) in the wood
average velocity (in the wood) ... (395 m/s + 102 m/s) / 2
thickness = average velocity * transit time
average velocity (in the wood) ... (395 m/s + 102 m/s) / 2
thickness = average velocity * transit time