Sr(OH)2 is a strong base and HI is a strong acid; therefore, SrI2 does not hydrolyze. The pH of salts of strong acids and strong bases will not shift the equilibrium of the H2O --> H^+ + OH^- and the pH will remain 7.00.
Note: Technically, the pH will not be 7.00 (it will be very close to 7.00) due to the Debye-Huckel effect and the ionic strength of the salt but this is an advanced topic and I assume it doesn't apply here.
Calculate the pH of a 0.51 M solution of SrI2. Record your pH value to 2 decimal places.
1 answer