Asked by Kendra
Simplify: 2(â+đ)^5/ 3(âđ+â)^3 x 3(ââđ)^6/ 14(g+h)^4
Answers
Answered by
oobleck
2(h+g)^5 / 3(h-g)^3 * 3(h-g)^6 / 14(h+g)^4
2(h+g)^5 / 14(h+g)^4 * 3(h-g)^6 / 3(h-g)^3
(h+g)/7 * (h-g)^3
massage it more if you want
2(h+g)^5 / 14(h+g)^4 * 3(h-g)^6 / 3(h-g)^3
(h+g)/7 * (h-g)^3
massage it more if you want
Answered by
mathhelper
2(h+g)^5 / (3(-g + h)^3) * 3(h - g)^6 / (14(g+h)^4 )
= 2(h+g)^5 * 3(h-g)^6 / [3(h-g)^3 * 14(g+h)^4 ]
= 6(h + g)(h - g)^3 / 42
= (2/7)(h + g)(h - g)^3 , h â Âąg
= 2(h+g)^5 * 3(h-g)^6 / [3(h-g)^3 * 14(g+h)^4 ]
= 6(h + g)(h - g)^3 / 42
= (2/7)(h + g)(h - g)^3 , h â Âąg
Answered by
oobleck
oops - lost that factor of 2
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