Question
The vector position of a particle varies in time according to the expression = (8.00 - 8.40t2 ) m. What is the velocity and acceleration as a function of time?
Answers
oobleck
s = 8.00 - 8.40t^2 m
v = ds/dt = -16.8t m/s
a = dv/dt = -16.8 m/s^2
v = ds/dt = -16.8t m/s
a = dv/dt = -16.8 m/s^2