Asked by carlton
The vector position of a 3.75 g particle moving in the xy plane varies in time according to the following equation.
At the same time, the vector position of a 5.20 g particle varies according to the following equation.
For each equation, t is in s and r is in cm. Solve the following when t = 2.00
(a) Find the vector position of the center of mass.
cm
cm
(b) Find the linear momentum of the system.
g-cm/s
g-cm/s
(c) Find the velocity of the center of mass.
cm/s
cm/s
(d) Find the acceleration of the center of mass.
cm/s2
cm/s2
(e) Find the net force exerted on the two-particle system.
μN
μN
At the same time, the vector position of a 5.20 g particle varies according to the following equation.
For each equation, t is in s and r is in cm. Solve the following when t = 2.00
(a) Find the vector position of the center of mass.
cm
cm
(b) Find the linear momentum of the system.
g-cm/s
g-cm/s
(c) Find the velocity of the center of mass.
cm/s
cm/s
(d) Find the acceleration of the center of mass.
cm/s2
cm/s2
(e) Find the net force exerted on the two-particle system.
μN
μN
Answers
Answered by
Henry
Where is the "following Eq"?
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