Asked by Wisdom
A water resrvoir in form of a cone is mounted on a hemispherical bowl.if the height of that one is six times its radius and the volume of the resevoir is 333 1/3 pi cm cubic,calculate correct to decimal place. a) the total surface area of the resevoir. b) curved surface area of the cone. c) volume of the reservoir
Answers
Answered by
Wisdom
Thank you
Answered by
oobleck
r=6h, so
v = π/3 r^2h = 12πh^3 = 1000/3 π, so h = 3 cm
the slant height s=√(h^2+r^2) = √(3^2+18^2) = 18.25
(a) πr(r+s)
(b) πrs
(c) you just said the volume was 333 1/3 π
But I don't see any mention of the hemisphere, which was apparently not part of the reservoir. Check for typos and make any fixes needed. And I know you have made some typos.
v = π/3 r^2h = 12πh^3 = 1000/3 π, so h = 3 cm
the slant height s=√(h^2+r^2) = √(3^2+18^2) = 18.25
(a) πr(r+s)
(b) πrs
(c) you just said the volume was 333 1/3 π
But I don't see any mention of the hemisphere, which was apparently not part of the reservoir. Check for typos and make any fixes needed. And I know you have made some typos.
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