Asked by Diana
A water reservoir in the form of a cone mounted on a hemispere is built such that the plane face of the hemisphere is built fits exactly to the base of the cone and the height of the cone is 6 times the radius of its base.
(a) Illustrate this information in a diagram,
(b) If the volume of the reservoir is 3331/3 pi m3 , calculate, correct to the nearest whole number, the:
(i) volume of the hemisphere
(ii) total surface area of the reservoir. (Take pi = 22/7)
(a) Illustrate this information in a diagram,
(b) If the volume of the reservoir is 3331/3 pi m3 , calculate, correct to the nearest whole number, the:
(i) volume of the hemisphere
(ii) total surface area of the reservoir. (Take pi = 22/7)
Answers
Answered by
oobleck
Is this physics or geometry?
If the radius of the hemisphere (and cone base) is r, then the volume of the hemisphere + cone is
2/3 π r^3 + 1/3 π r^2 (6r) = 8/3 π r^3
The area is thus 2πr^2 + 2π√37 r^2
You can use your given volume to find r.
If the radius of the hemisphere (and cone base) is r, then the volume of the hemisphere + cone is
2/3 π r^3 + 1/3 π r^2 (6r) = 8/3 π r^3
The area is thus 2πr^2 + 2π√37 r^2
You can use your given volume to find r.
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