Asked by Wilson
A block and tackle with a velocity ratio of 6 is used to lift a load of mass 30kg through a vertical distance of 40cm at a steady rate. If the effort is 60newtons, determine the loss in energy.
Answers
Answered by
Anonymous
Work accomplished = 30 * 0.4 * g = 12 * 9.8 Joules =118 Joules
Work in = 60 * 0.4 * 6 = 144 Joules
so 144 - 118 Joules
Work in = 60 * 0.4 * 6 = 144 Joules
so 144 - 118 Joules
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