Question
A block and tackle have 4 pulleys which is used to raise a load of 450N through a height of 12m. If the workdone against friction is 1000J, calculate the workdone by the effort, the efficiency of the system and the effort applied.
Answers
work on load = 450 N * 12 m = 5.4kJ
effort distance = 4 * 12 m = 48 m
effort work = 1000 J + 5.4 kJ = 6.4 kJ
efficiency = (work on load) / effort work
effort applied = (effort work) / (effort distance)
effort distance = 4 * 12 m = 48 m
effort work = 1000 J + 5.4 kJ = 6.4 kJ
efficiency = (work on load) / effort work
effort applied = (effort work) / (effort distance)
Related Questions
A block and tacle of 6 pulley is used to raise a load of 300n steadily through a height of 30m if th...
A block and tackle system of pulleys consisting of 4 pulleys is used to raise a load of 50N through...
A block and tackle consisting of 5 pulleys is used to raise a load of 400N through a height of 10m....