Asked by ran
x + 2sqrt(x ^ 3 + 3x ^ 2 + 5x + 6)
Answers
Answered by
mathhelper
You posed no question, so the only thing I notice is that
x^3 + 3x^2 + 5x + 6 = (x+2)(x^2 + x + 2)
we could write x + 2√( (x ^ 3 + 3x ^ 2 + 5x + 6) ) as
(x+2) + (x+2)^(1/2) * (x^2 + x + 2)^(1/2)
and then factor out √(x+2) as ...
(x+2)^(1/2) [ (x+2)^(1/2) + (x^2 + x + 2)^(1/2) ]
but we would be "complicating" this instead of simplifying.
x^3 + 3x^2 + 5x + 6 = (x+2)(x^2 + x + 2)
we could write x + 2√( (x ^ 3 + 3x ^ 2 + 5x + 6) ) as
(x+2) + (x+2)^(1/2) * (x^2 + x + 2)^(1/2)
and then factor out √(x+2) as ...
(x+2)^(1/2) [ (x+2)^(1/2) + (x^2 + x + 2)^(1/2) ]
but we would be "complicating" this instead of simplifying.
Answered by
oobleck
x^3 + 3x^2 + 5x + 6 = (x+2)(x^2 + x + 3)
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