FIND THE ANGLES BETWEEN 0degree and 360degree whose sine is 0.9962
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Answered by
SINE AND CO-SINE RULES AND THEIR APPLICATION
Give me the solution
Answered by
oobleck
your reference angle is θ such that
sinθ = 0.9962
θ = 85°
sine is positive in QI and QIIso your solutions are
θ and 180-θ
sinθ = 0.9962
θ = 85°
sine is positive in QI and QIIso your solutions are
θ and 180-θ
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