Asked by SEXA
The sum of interior angles of a regular polygon is 1800\degree1800°1800, degree.
Find the measure of each interior angle of the polygon.
Find the measure of each interior angle of the polygon.
Answers
Answered by
Anonymous
Huh?
Answered by
Bosnian
The sum of interior angles of a yours regular polygon is 1800°
Use property:
Sum of interior angles = ( n - 2 ) ∙ 180°
In this case sum of interior angles = 1800°
So:
( n - 2 ) ∙ 180° = 1800°
Divide both sides by 180°
n - 2 = 10
Add 2 to both sides
n = 12
If he sum of interior angles of a yours regular polygon is 1800° then interior angles are:
Sum of interior angles / number of sides
In this case interior angles are:
1800° / 12 = 150°
Use property:
Sum of interior angles = ( n - 2 ) ∙ 180°
In this case sum of interior angles = 1800°
So:
( n - 2 ) ∙ 180° = 1800°
Divide both sides by 180°
n - 2 = 10
Add 2 to both sides
n = 12
If he sum of interior angles of a yours regular polygon is 1800° then interior angles are:
Sum of interior angles / number of sides
In this case interior angles are:
1800° / 12 = 150°
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