Asked by Andrew
The resistance ( R ) to a motion of a car is partly constant and partly varies as the square of the speed ( V ) When the car is moving at ( 20KM/H ) The resistance is (720 OHMS ) and at ( 60KM/H ) the resistance is 232 ohms fine an expression for ( R ) of ( V ) the resistance at 40km/h
Answers
Answered by
mathhelper
R = c + kV^2
when V = 20, R = 720
c + 400k = 720
when V = 60, R = 232
c + 3600k = 232
subtract the two equations ...
3200k = -488
k = -61/400
back in first equation:
c + 400(-61/400) = 720
c = 781
R = 781 - (61/400) V^2
Now that we have the equation, you can finish your question.
when V = 20, R = 720
c + 400k = 720
when V = 60, R = 232
c + 3600k = 232
subtract the two equations ...
3200k = -488
k = -61/400
back in first equation:
c + 400(-61/400) = 720
c = 781
R = 781 - (61/400) V^2
Now that we have the equation, you can finish your question.
Answered by
TERNGU
SIR
Answered by
TERNGU
SAMUEL
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