Asked by Joy
How do you solve these types of problems?
1) 3 - n = 32
3m - 8n - 6 = 0
2) 2p - q = 8
1/3p + 1/4q = 3
1) 3 - n = 32
3m - 8n - 6 = 0
2) 2p - q = 8
1/3p + 1/4q = 3
Answers
Answered by
drwls
1. substitute -29 for n in the second equation, and solve for q.
(n=-29 comes from the first equation)
2. Multiply the second equation by 4 and add them.
2p - q = 8
4/3p + q = 12
10/3 p = 20
p = 6
q = 2p - 8 = 4
(n=-29 comes from the first equation)
2. Multiply the second equation by 4 and add them.
2p - q = 8
4/3p + q = 12
10/3 p = 20
p = 6
q = 2p - 8 = 4
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