7exponent to the power of 2yto the power of3 mines 14xyto the power of 2

Question

Answer 1

mathhelper answered
3 years ago

why not simply say:

(7^2)y^3 - 14xy^2
= 49y^3 - 14xy^2
= 7y^2(7y - 2x)

mines? somebody working in gold mines?

Answer 2

oobleck answered
3 years ago

7^2 y^3 - (14xy)^2
= 49y^3 - 196x^2y^2
= 49y^2 (y-4x^2)

next time type what you want, instead of dictating it in ambiguous words.