((√(x-3))/(x-2)>0 , (the x-2 is not included in the √ operation.)
clearly x ≠ 2, and x ≥ 3
The x≠2 restriction is included in x ≥ 3
for any x ≥ 3, then numerator is positive, and the denominator is positive,
so it looks like we can simply say:
x ≥ 3
Find the values of x
((root(x-3))/(x-2)>0
Urgent
3 answers
actually, just x > 3
since we want the fraction to be > 0
since we want the fraction to be > 0
correct, I missed that > vs ≥