Question
What mass of CO2 could be produced from 14.8 g of C2H5OH? Assume C2H5OH is the limiting reactant.
What mass of O2 would be consumed?
What mass of H2O would be produced?
What mass of O2 would be consumed?
What mass of H2O would be produced?
Answers
DrBob222
C2H5OH + 3O2 ==> 2CO2 + 3H2O
mols C2H5OH = grams/molar mass = 14.8/0.46 = 0.321
mols CO2 = mols C2H5OH x (2 mols CO2/1 mol C2H5OH) = 0.321 x 2 = 0.642. Then grams CO2 = mols CO2 x molar mass CO2 = ?
The other two parts of the problem are worked the same way. Post your work if you get stuck.
mols C2H5OH = grams/molar mass = 14.8/0.46 = 0.321
mols CO2 = mols C2H5OH x (2 mols CO2/1 mol C2H5OH) = 0.321 x 2 = 0.642. Then grams CO2 = mols CO2 x molar mass CO2 = ?
The other two parts of the problem are worked the same way. Post your work if you get stuck.