Asked by Annabelle
Determine the mass of the products formed by the combustion of a 7.6g of a coumpound with emprical formula C7H12
Answers
Answered by
DrBob222
C7H12 + 10O2 ==> 7CO2 + 6H2O
moles C7H12 = 7.6g/96 = estimated 0.08
mols CO2 = 0.08mols C7H12 x (7 mols CO2/1 molC7H12) = estimated 0.55
Then mass = mols CO2 x molar mass CO2 = ?
Do the same for mols C7H12 to mols H2O, convert mols H2O to grams. then add the g CO2 + g H2O = total grams products.
moles C7H12 = 7.6g/96 = estimated 0.08
mols CO2 = 0.08mols C7H12 x (7 mols CO2/1 molC7H12) = estimated 0.55
Then mass = mols CO2 x molar mass CO2 = ?
Do the same for mols C7H12 to mols H2O, convert mols H2O to grams. then add the g CO2 + g H2O = total grams products.
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