Asked by Sam
Eugenol, a compound found in nutmeg and cloves, has the formula C10H12O2. What is the boiling point of a solution containing 0.144 g of this compound dissolved in 10.0 g of benzene?
Molar mass of C10H12O2 = 164.2 g/mol kb of benzene= 2.53 °C/m
Soultion?
Molar mass of C10H12O2 = 164.2 g/mol kb of benzene= 2.53 °C/m
Soultion?
Answers
Answered by
DrBob222
delta T = Kb*m
m = molality = mols/kg solvent
mols = grams/molar mass
mols = 0.144/164.2 = ?
m = ?mols/0.01 = ?
delta T = 2.53*m
Add delta T to the normal boiling point of benzene to find the new boiling point of benzene. You will need to look up the value for the boiling point of benzene. I seem to remember 80.2 degrees C but you should confirm that. I don't have all of the boiling points of thousands upon thousands of compounds memorized and I'm not even working on that project.
m = molality = mols/kg solvent
mols = grams/molar mass
mols = 0.144/164.2 = ?
m = ?mols/0.01 = ?
delta T = 2.53*m
Add delta T to the normal boiling point of benzene to find the new boiling point of benzene. You will need to look up the value for the boiling point of benzene. I seem to remember 80.2 degrees C but you should confirm that. I don't have all of the boiling points of thousands upon thousands of compounds memorized and I'm not even working on that project.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.