A compound is found to contain 63.52 % iron and 36.48 % sulfur. Find its empirical formula.

Question

FeS
FeS2
Fe2S
Fe2s3

Answer 1

look at 100 g of the compound

63.52 g Fe and 36.48 g S

the formula is by moles
... so divide the weights by the molar masses
... the ratio of the quotients is the ratio of the atoms
... 1:1 , 1:2 etc.