Asked by Clueless
A compound is found to contain 63.52 % iron and 36.48 % sulfur. Find its empirical formula.
FeS
FeS2
Fe2S
Fe2s3
FeS
FeS2
Fe2S
Fe2s3
Answers
Answered by
Scott
look at 100 g of the compound
63.52 g Fe and 36.48 g S
the formula is by moles
... so divide the weights by the molar masses
... the ratio of the quotients is the ratio of the atoms
... 1:1 , 1:2 etc.
63.52 g Fe and 36.48 g S
the formula is by moles
... so divide the weights by the molar masses
... the ratio of the quotients is the ratio of the atoms
... 1:1 , 1:2 etc.
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