Question

A woman standing on the surface of the Earth, 6.38 x 106 meters from its center, has a mass of 57.0 kg. If the mass of the Earth is 5.98 x 1024 kg, what is the force of gravity on the woman?

Answers

oobleck
F = GMm/r^2 = (6.67*10^-11)(5.98*10^24)(57.0)/(6.38^10^6)^2
= 558.55 N

Hmmm. 9.81 * 57 = 559.17
Must be some rounding error in the calculation, or in the values given.
R_scott
the Earth is an oblate spheroid

gravitational force is not uniform over the surface

9.81 is an "average" value

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