I found on the web that saturated water vapor @ 200 kPa had a temperature of 120.21 C and the volume was 0.88576 m^3/kg. So 5 kg will have a volume of 0.88576 m^3/kg x 5 kg = 4.4288 m^3 = V1. I was unable to find the volume at 300 C; however, assuming ideal behavior PV = nRT can be used to calculate volume @ 300 C. That gives you V2.
Then work = - p(V2-V1). The units will be in kPa*m^3 which may not be the units you want but those can be changed to what you wish.
A mass of 5kg of saturated water vapour at 200kPa is heated at constant pressure until
the temperature reaches 300oC. Calculate the work done by the steam during this process.
1 answer
1 answer