Asked by Joel Santos
A mass of 5kg of saturated water vapour at 200kPa is heated at constant pressure until
the temperature reaches 300oC. Calculate the work done by the steam during this process.
the temperature reaches 300oC. Calculate the work done by the steam during this process.
Answers
Answered by
DrBob222
I found on the web that saturated water vapor @ 200 kPa had a temperature of 120.21 C and the volume was 0.88576 m^3/kg. So 5 kg will have a volume of 0.88576 m^3/kg x 5 kg = 4.4288 m^3 = V1. I was unable to find the volume at 300 C; however, assuming ideal behavior PV = nRT can be used to calculate volume @ 300 C. That gives you V2.
Then work = - p(V2-V1). The units will be in kPa*m^3 which may not be the units you want but those can be changed to what you wish.
Then work = - p(V2-V1). The units will be in kPa*m^3 which may not be the units you want but those can be changed to what you wish.
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