Asked by BigBoiMark
1. Simplify. (-8x^3 +4x + 1) / (2x + 1)
2. The width w of a rectangular swimming pool is x + 4. The areaa A of the pool is x^3 - 13x + 12. What is an expression for the length of the pool?
2. The width w of a rectangular swimming pool is x + 4. The areaa A of the pool is x^3 - 13x + 12. What is an expression for the length of the pool?
Answers
Answered by
Shawn
anyone got an anwser
Answered by
Molly
I think its for connexus for the test does anyone got anwsers
Answered by
Gabby
so many people have visited this question
Answered by
Pro-Truth-Efficient
Its might be fake. Just refreshing a lot
Answered by
Gabby
well still do we know the answers
Answered by
oobleck
You know, guys, unless you actually have a correct answer to the questions, your vacuous posts serve no purpose.
(-8x^3 +4x + 1) / (2x + 1)
= (-4x^2+2x+1)(2x+1) / (2x+1)
= -4x^2+2x+1 for x ≠ -1/2
since area = width * length,
length = area/width = (x^3 - 13x + 12)/(x+4)
= (x-1)(x-3)(x+4) / (x+4)
= (x-1)(x-3)
= x^2-4x+3
(-8x^3 +4x + 1) / (2x + 1)
= (-4x^2+2x+1)(2x+1) / (2x+1)
= -4x^2+2x+1 for x ≠ -1/2
since area = width * length,
length = area/width = (x^3 - 13x + 12)/(x+4)
= (x-1)(x-3)(x+4) / (x+4)
= (x-1)(x-3)
= x^2-4x+3
Answered by
CookieCrumbs/Pro-Truth-Efficient
If you know DrBob222, then you should check into our debate in the chat:
Chemistry
A 10.0 mL sample of hydrochloric acid solution with an unknown concentration is titrated with a 0.10 mol/L solution of potassium hydroxide. The results of the titration are shown in the table below:
Trial Initial volume of KOH (mL) Final volume of KOH (mL)
1 6.00 15.34
2 15.34 24.32
3 4.61 13.98
What is the concentration of the hydrochloric acid?
By: Carl/Listest in the newest section
(-_-)
It's getting interesting, and I would love a 2v1
Chemistry
A 10.0 mL sample of hydrochloric acid solution with an unknown concentration is titrated with a 0.10 mol/L solution of potassium hydroxide. The results of the titration are shown in the table below:
Trial Initial volume of KOH (mL) Final volume of KOH (mL)
1 6.00 15.34
2 15.34 24.32
3 4.61 13.98
What is the concentration of the hydrochloric acid?
By: Carl/Listest in the newest section
(-_-)
It's getting interesting, and I would love a 2v1
Answered by
Anonymous
I'll post the answers in a few minutes
Answered by
ay
its been more then a few minutes
Answered by
Its been way more than a few
MINUTES
Answered by
Lili
ANSWERS:
1. A -6x²+4x+3
2. D x²+2x+2
3. A 110/x
4. C 1/7+x ;where x=0,-7
5. A 5/7+x ; where x=0,-7
6. B 1/x+6 ; were x= -6,2
7. A x-5; where x= -2
8. D 35/2a³ ; where a=0
9. D (x+2)(2x+1)
10. A x-4/x-1
11. B (x+1)(x+4)/(x-4)
12. D 6t³ - 4t⁵
13. C -3m⁶ -3m⁵ -8m³
14. A -5x-7/x+3
15. B 3x-33/(x+7)(x-2)
16. B 10x+26/(x-3)(x+5)
17. D x = -2
18. B x = 9/2
19. B x = -5,-3
20. B 3.43 hours
21. D about 8.47 hours
22. A direct variation; y = 4x
23. C x = -16
1. A -6x²+4x+3
2. D x²+2x+2
3. A 110/x
4. C 1/7+x ;where x=0,-7
5. A 5/7+x ; where x=0,-7
6. B 1/x+6 ; were x= -6,2
7. A x-5; where x= -2
8. D 35/2a³ ; where a=0
9. D (x+2)(2x+1)
10. A x-4/x-1
11. B (x+1)(x+4)/(x-4)
12. D 6t³ - 4t⁵
13. C -3m⁶ -3m⁵ -8m³
14. A -5x-7/x+3
15. B 3x-33/(x+7)(x-2)
16. B 10x+26/(x-3)(x+5)
17. D x = -2
18. B x = 9/2
19. B x = -5,-3
20. B 3.43 hours
21. D about 8.47 hours
22. A direct variation; y = 4x
23. C x = -16
Answered by
Nightwolf
@Lili, for the Unit 6 Lesson 8 Test, your answers are incorrect.
Answered by
Lili
@Nightwolf, those answers are for the test, but they change the order of the questions for some people so that’s why they might not work for you.
Answered by
amazing person
Heres the answers to the Unit 6: lesson 8 test
1.b
2. d
3.a
4.c
5.b
6.a
7.b
8.c
9.c
10.a
11.a
12.a
13.a
14.c
15.a
16.d
17.a
18.b
19.c
20.b
21.d
22.c
23.d
1.b
2. d
3.a
4.c
5.b
6.a
7.b
8.c
9.c
10.a
11.a
12.a
13.a
14.c
15.a
16.d
17.a
18.b
19.c
20.b
21.d
22.c
23.d
Answered by
@amazing person
Ur wrong I got a 47% ("-_-)
Answered by
@@amazing person
You could've posted answers bruh
Answered by
Money Man
I will get yall your answers soon once I finish this test
Answered by
no bot
no bot, because we would rather rely on you to do all our thinking and work XD
Answered by
no bot
stoppppp it bot, get away
Answer
Still waiting for the answers
Answered by
the
go to hell bot
Answered by
Hummushustler299
1/x - 6/x^2 = -12?
Answered by
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Answered by
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As an AI language model, I cannot complete your exam or provide you with the answers to any exam or test. It is important to do your best and complete the exam on your own to ensure an accurate representation of your knowledge and skills. Cheating is not only against school policies but also hinders your ability to learn and retain knowledge that will be essential in your future educational and professional pursuits.
Answered by
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Answered by
Bot
To solve the equation 1/x - 6/x^2 = -12, you can follow these steps:
1. Simplify the left side of the equation using a common denominator.
1/x - 6/x^2 = (x/x^2) - (6/x^2) = (x - 6) / x^2
2. Substitute the simplified expression into the original equation.
(x - 6) / x^2 = -12
3. Multiply both sides of the equation by x^2 to eliminate the denominator.
(x - 6) = -12x^2
4. Rearrange the equation to get a quadratic equation in standard form, ax^2+bx+c=0.
12x^2 + x - 6 = 0
5. Solve the quadratic equation either by factoring, completing the square, or using the quadratic formula.
Using the quadratic formula:
x = (-1 ± sqrt(1^2 - 4(12)(-6))) / (2(12))
x = (-1 ± sqrt(1 + 288)) / 24
x = (-1 ± sqrt(289)) / 24
x = (-1 ± 17) / 24
x = 16/24 or x = -18/24
x = 2/3 or x = -3/4
Therefore, the solutions to the equation are x = 2/3 or x = -3/4.
1. Simplify the left side of the equation using a common denominator.
1/x - 6/x^2 = (x/x^2) - (6/x^2) = (x - 6) / x^2
2. Substitute the simplified expression into the original equation.
(x - 6) / x^2 = -12
3. Multiply both sides of the equation by x^2 to eliminate the denominator.
(x - 6) = -12x^2
4. Rearrange the equation to get a quadratic equation in standard form, ax^2+bx+c=0.
12x^2 + x - 6 = 0
5. Solve the quadratic equation either by factoring, completing the square, or using the quadratic formula.
Using the quadratic formula:
x = (-1 ± sqrt(1^2 - 4(12)(-6))) / (2(12))
x = (-1 ± sqrt(1 + 288)) / 24
x = (-1 ± sqrt(289)) / 24
x = (-1 ± 17) / 24
x = 16/24 or x = -18/24
x = 2/3 or x = -3/4
Therefore, the solutions to the equation are x = 2/3 or x = -3/4.
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