Asked by Copper

Pls help me I need help!!!!For problems 1-4, solve the given system of equations using either substitution or elimination.
1.
2x + y = -8
y = 2x + 4

A. (-4, 0)
B. (-3, -2)
C. (1, 6)
D. infinitely many solutions
Lesson 2 unit 5 in connects 8th
Answered by mathhelper
perfectly suited for substitution

2x + y = -8
2x + (2x+4) = -8
2x + 2x + 4 = -8

your turn, once you have the x, sub it back into y = 2x+4 for your y
Answered by Copper
I need the answers
Answered by unknown:)
B
C
A
D

i just took the connections quick check for solving systems of equations algebraically 100% correct
Answered by Connexus Student
Unknown:) Is correct for unit 5 lesson 2 quick check for 8th grade pre algebra
Answered by Teeth
Unknown is still correct for 2022! :3
Answered by Anonymous
thx unknown
Answer
This concept rlly does not make any sense
Answer
I need help with it
Answer
2x+5y=×
X-2y=x
Answer
2+5y=×
Answer
3x - 5y= -22
Answer
I need help too
Answer
3x - 5y = -22
Answered by Is he right let me know
What’s the answer bot
Answered by Bot
I'm sorry to hear that you are struggling with this concept. Solving systems of equations using substitution or elimination can be tricky, but with practice and patience, it can be mastered. If you have any specific questions or examples you want to solve, feel free to ask and I'll be happy to help you.
Answered by Bot
Sure! Can you please provide me with a specific system of equations that you are struggling to solve using substitution or elimination method?
Answered by Bot
I believe there's a typo in the first equation. Can you please give me the correct value of "= x" in the first equation so I can solve the system for you?
Answered by Bot
I think you missed giving me the value of "x" in the first equation again. Can you please provide me with the correct value of "x" in the first equation so I can help you solve the system of equations?
Answered by Bot
Sure! What system of equations do you need help with?
Answered by Bot
To solve the given system of equations using the substitution method, we can solve one equation for one variable and substitute it into the other equation. Here, we can solve the second equation for x as follows:

x - 2y = x
x = 2y

Now, substitute x = 2y into the first equation:

3x - 5y = -22
3(2y) - 5y = -22
6y - 5y = -22
y = -22

Finally, substitute y = -22 into x = 2y to get:

x = 2y
x = 2(-22)
x = -44

Therefore, the solution to the system of equations 3x - 5y = -22 is (x, y) = (-44, -22).