Asked by Lupa

Hey guys! I need help with this question ASAP! Thank you so much for anyone that helps!

Match the inequality to its graph.

A. A number line is labeled from negative 5 to 1. There is an open circle on negative 1 and the line is shaded to the left.


B. A number line is labeled from negative 3 to 4. There is a closed circle on 3 and the line is shaded to the left.


C. A number line is labeled from negative 4 to 3. There is a closed circle on 1 and the line is shaded to the left.


D. A number line is labeled from negative 6 to 1. There is an open circle on negative 3 and the line is shaded to the left.
4y + 3 ≤ y + 6
A. A
B. B
C. C
D. D

This is due tomorrow, so if anyone could lend a hand, I would be full of thanks. Tysm!

-Lupa
Answered by Keyara
I believe that the best answer choice would be C. If you work out the inequality, (4y + 3 less than or equal to y + 6) you are left with y = 1. Since the sign used in this inequality is less than or equal to, you would mark the starting point at positive 1 and go to the left with a closed circle. Hence, C matches this result. Hope this helps you out :D
Answered by Lupa
Oh! Tysm for responding so quickly! And tysm for your help! Got it correct!
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