Asked by Anonymous
using calculus, find the area bounded by y=cos(x), y=x, and y=-x
Answers
Answered by
mathhelper
We need the intersection of y = cosx and y = x
This is the most difficult part of this question, once you have that
we simply have ....
area = 2 ∫ (cosx - x) dx from x = 0 to k, where k is intersection value.
let's use Wolfram to solve cosx = x
x = .739085
www.wolframalpha.com/input/?i=solve+cosx+%3D+x
Area = 2[sinx - x^2/2] | from 0 to .739085
= 2[ (sin .739085 - (.739085^2)/2) - (0-0) ]
= appr .801
This is the most difficult part of this question, once you have that
we simply have ....
area = 2 ∫ (cosx - x) dx from x = 0 to k, where k is intersection value.
let's use Wolfram to solve cosx = x
x = .739085
www.wolframalpha.com/input/?i=solve+cosx+%3D+x
Area = 2[sinx - x^2/2] | from 0 to .739085
= 2[ (sin .739085 - (.739085^2)/2) - (0-0) ]
= appr .801
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