Asked by Cyril
A car moves with a velocity of 72kmh^1 it is brought to rest in 105 find (1)the velocity in ms^1 (2)the retardiationm show solvings
Answers
Answered by
Anonymous
72 km/hr ( 1 hr/3600s)(1000 m/km) = 20 m/s
assume you want the acceleration in 105 seconds = - 20/105 = - 0.19 m/s^2
but perhaps you mean 105 meters
av speed = 10m/s^2
so time to stop = 105/10 = 10.5 seconds
thenacceleration = -20 m/2 /10.5 s = - 1.9 m/s^2
assume you want the acceleration in 105 seconds = - 20/105 = - 0.19 m/s^2
but perhaps you mean 105 meters
av speed = 10m/s^2
so time to stop = 105/10 = 10.5 seconds
thenacceleration = -20 m/2 /10.5 s = - 1.9 m/s^2
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.