Asked by Jonathan
A particle moves with velocity function v(t) = 2t^2 − 3t − 3, with v measured in feet per second and t measured in seconds. Find the acceleration of the particle at time t = 2 seconds.
a)3/4 feet per second^2
b)-1 feet per second^2
c)32 feet per second^2
d)5 feet per second^2
a)3/4 feet per second^2
b)-1 feet per second^2
c)32 feet per second^2
d)5 feet per second^2
Answers
Answered by
Damon
a = 4 t -3
s(2) = 8-3 = 5
s(2) = 8-3 = 5
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