The average value of f(x) on the interval [a,b] is just
∫[a,b] f(x) dx / (b-a)
so plug in your numbers.
Come back with your work if you get stuck.
If this problem is only worth 1 point, it shouldn't be too hard ...
(1 point) This is similar to a problem from the Hughes-Hallett textbook. Use the Fundamental Theorem of Calculus to evaluate the average value of f(x)=9x^(2)+2 on the interval x=0 to x=8
1 answer