Asked by SAAD
The molar solubility of gold(I) chloride is 4.510-7 mol/L. Calculate the solubility constant of this
compound.
compound.
Answers
Answered by
DrBob222
.......................AuCl(s) ----> Au^+ + Cl^-
I.......................solid...............0.........0
C.....................solid-x.............x..........x
E......................solid................x..........x
Ksp = (Au^+)(Cl^-) = (x)(x)
The problem tells you that x = 4.5E-7
Substitute that number and solve for Ksp.
Post your work if you get stuck.
I.......................solid...............0.........0
C.....................solid-x.............x..........x
E......................solid................x..........x
Ksp = (Au^+)(Cl^-) = (x)(x)
The problem tells you that x = 4.5E-7
Substitute that number and solve for Ksp.
Post your work if you get stuck.
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