Asked by Maegan G
What is the molar solubility of copper(II) carbonate at 25 oC in a solution that is 0.055 M in copper(II) chloride?
I have done one and I am not sure I am doing it correct. If you can show your work for myself to understand. That would be awesome. Thank You!!
I have done one and I am not sure I am doing it correct. If you can show your work for myself to understand. That would be awesome. Thank You!!
Answers
Answered by
DrBob222
It would have been far easier for you to show your work and let us tell you where your weak/strong points are. As it is I do all the typing and you compare. Henceforth, you type and we will compare.
CuCO3(s)==> Cu^2+ + CO3^-
...x.........x.......x
.........CuCl2(aq) ==> Cu^2+ + 2Cl^-
initial..0.055...........0......0
final soln..0.........0.055..2*0.055
Ksp CuCO3 = (Cu^2+)(CO3^2-)
Ksp = (x+0.055)(x)
Solve for x = solubility CuCO3.
Note: This is a common ion problem with the Cu(II) from CuCl2 being the common ion. Therefore the concn Cu(II) is x from the CuCO3 and 0.055 from the CuCL2.
CuCO3(s)==> Cu^2+ + CO3^-
...x.........x.......x
.........CuCl2(aq) ==> Cu^2+ + 2Cl^-
initial..0.055...........0......0
final soln..0.........0.055..2*0.055
Ksp CuCO3 = (Cu^2+)(CO3^2-)
Ksp = (x+0.055)(x)
Solve for x = solubility CuCO3.
Note: This is a common ion problem with the Cu(II) from CuCl2 being the common ion. Therefore the concn Cu(II) is x from the CuCO3 and 0.055 from the CuCL2.
Answered by
Anonymous
wow- fiesty drbob
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