g(2) = 11
g(8) = 29
average value of g(t) = (29+11)/2 = 20
(1 point)
Find the average value of g(t)=3t+5 over the interval [2,8]. Round your answer to the nearest hundredth.
3 answers
the average value of g(t) over [a,b] is ∫[a,b] g(t) dx / (b-a)
so now you have
∫[2,8] (3t+5) dt / (8-2)
= 120/6
= 20
so now you have
∫[2,8] (3t+5) dt / (8-2)
= 120/6
= 20
LOL
the value in the middle. It is linear.
g(5) = 20
the value in the middle. It is linear.
g(5) = 20