Asked by Ray
The fountain is made up of two semicircles, the 2 semicircles have a radius of 10ft, and a quarter circle. Find the perimeter and the area of the fountain. Round the perimeter to the nearest tenth of a foot and the area to the nearest square foot.
Answers
Answered by
oobleck
You don't say how the parts are arranged. If no portion of the diameters overlaps. then just add all the semi-circle perimeters. Since you don't specify the radius of the quarter-circle, I'll assume that it is also 10 ft. Given all that, the perimeter is just
2*10 + 5 + 2*5π + 5π = 25+15π
The area would be
2*25π + 25/4 π = 225π/4
2*10 + 5 + 2*5π + 5π = 25+15π
The area would be
2*25π + 25/4 π = 225π/4
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