Asked by Jean
The units digit of a two-digit number is one-half the tenths digits, when the digits are reverse the new number is 15 more than twice the number. Find the original number.
Answers
Answered by
oobleck
If the digits are a,b then a = 2b
10b+a = 15+2(10a+b)
10b+2b = 15+2(20b+b)
12b = 15+42b
I suspect a typo. Let's see.
The only possible numbers are 21,42,63,84
The reversed numbers would be 12,24,36,48
In each case, the reversed number is less than the original.
10b+a = 15+2(10a+b)
10b+2b = 15+2(20b+b)
12b = 15+42b
I suspect a typo. Let's see.
The only possible numbers are 21,42,63,84
The reversed numbers would be 12,24,36,48
In each case, the reversed number is less than the original.
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