Google Gauss
E = (1/ 4 pi eo) Q /r^2
here R = 0.15 meter
Q = 10 *10^-6 = 10^-5 Coulomb
= ( 9 *10^9 Nm^2/C^2)(10^-5 C) / 0.0225 m^2
E = (1/ 4 pi eo) Q /r^2
here R = 0.15 meter
Q = 10 *10^-6 = 10^-5 Coulomb
= ( 9 *10^9 Nm^2/C^2)(10^-5 C) / 0.0225 m^2
Why did the scarecrow win an award?
Because he was outstanding in his field!
But since you asked, the electric intensity at a point 15cm from a charge of 10 microcoulomb can be calculated using the formula:
E = (k * q) / r^2
where E is the electric intensity, k is the Coulomb constant (9 × 10^9 N m^2/C^2), q is the charge, and r is the distance. Plugging in the values, we have:
E = (9 × 10^9 N m^2/C^2 * 10 × 10^(-6) C) / (0.15 m)^2
Now, let's do the math... *whizzes and bangs around making calculations* ...and we get our answer!
But hey, who needs calculations when you've got jokes, right?
The formula for calculating electric intensity (E) is:
E = k * (Q / r^2)
Where:
- E is the electric intensity in Newtons per Coulomb (N/C).
- k is the electrostatic constant with a value of approximately 9 x 10^9 Nm^2/C^2.
- Q is the charge in Coulombs (C).
- r is the distance from the charge in meters (m).
Now, let's plug in the values into the formula:
Q = 10 microCoulomb = 10 x 10^-6 C
r = 15 cm = 15 x 10^-2 m (convert cm to m)
E = (9 x 10^9 Nm^2/C^2) * (10 x 10^-6 C) / (15 x 10^-2 m)^2
First, convert the distance to its square:
r^2 = (15 x 10^-2 m)^2 = 225 x 10^-4 m^2
Now substitute the values:
E = (9 x 10^9 Nm^2/C^2) * (10 x 10^-6 C) / (225 x 10^-4 m^2)
Simplify by cancelling units:
E = (9 x 10^9 N x m^2 x C^-2) * (10 x 10^-6 C) / (225 x 10^-4 m^2)
E = (9 x 10^9 N x m^2 x C^-2) * (10 x 10^-6) / (225 x 10^-4)
Now calculate the multiplication:
E = (9 x 10^9 N x m^2 x C^-2) * (10 x 10^-6) / (225 x 10^-4)
E = (9 x 10^9 N x m^2 x C^-2) * (10 x 10^-6) / (225 x 10^-4)
E = (9 x 10^9 N x m^2) * (10 x 10^-6) / (225 x 10^-4 x C^2)
Now simplify further:
E = (9 x 10^9 N x m^2) * (exp(10 - 6)) / (225 x 10^-4 x C^2)
E = 9 x (1/225) x 10^9 x (10^-6) x (10^4) N/C
Finally, perform the multiplication and division:
E = (9 / 225) x 10^9 x 10^-6 x 10^4 N/C
E = 0.04 x 10^9 N/C
E = 4 x 10^7 N/C
Therefore, the electric intensity at a point 15 cm from a charge of 10 microCoulomb is 4 x 10^7 N/C.