Asked by tristyn

A 0.050-m-long wire is carrying a current of 2.0 A at right angles to a 0.15-T magnetic field. What is the magnitude of the force exerted by the magnetic field on the wire?

please help asap

Answers

Answered by Anonymous
dF = I dL cross B
they are perpendicular so
F = I L B
= 2.0 * 0.050 * 0.15 Newtons
Answered by Anonymous
By the way, this is surely in your text.
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