A 0.050-m-long wire is carrying a current of 2.0 A at right angles to a 0.15-T magnetic field. What is the magnitude of the force exerted by the magnetic field on the wire?

Question

please help asap

Answer 1

dF = I dL cross B
they are perpendicular so
F = I L B
= 2.0 * 0.050 * 0.15 Newtons

Answer 2

By the way, this is surely in your text.