Asked by Please Help Me, I need to learn.
                If a solution containing 0.015 M each of bromide, chloride, iodide, and thiocyanate, is treated with Cu+, in what order will the anions precipitate?  
            
            
        Answers
                    Answered by
            DrBob222
            
    Take CuBr as an example: The Ksp value is 6.3E-9 but make sure you use the Ksp values in your notes or your text.
................CuBr ===> Cu^+ + Br^-
I................solid...........0...........0
C..............solid............x............x
E..............solid.............x............x
Ksp = 6.3E-9 = (Cu^+)(Br^-)
(Cu^+) = x
(Br^-) = 0.15 M from the problem.
Substitute
6.3E-9 = (x)(0.15)..
Then x = (Cu^+) = 6.3E-9/0.15 = ?
Do the same for all of the salts. The one with the smallest value for Cu will ppt first followed in order by the others. Post your work if you get stuck.
    
................CuBr ===> Cu^+ + Br^-
I................solid...........0...........0
C..............solid............x............x
E..............solid.............x............x
Ksp = 6.3E-9 = (Cu^+)(Br^-)
(Cu^+) = x
(Br^-) = 0.15 M from the problem.
Substitute
6.3E-9 = (x)(0.15)..
Then x = (Cu^+) = 6.3E-9/0.15 = ?
Do the same for all of the salts. The one with the smallest value for Cu will ppt first followed in order by the others. Post your work if you get stuck.
                    Answered by
            Please Help Me, I need to learn.
            
    Thank you so much for your help.
    
                                                    There are no AI answers yet. The ability to request AI answers is coming soon!
                                            
                Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.