Question

a rectangular pyramid that measures 10cm by 7cm has a height of 11cm. Cal,side of the triangle

Answer 1

divide that rectangular base, corners A, B, C, D into 4 rectangles each 5 by 3.5, call the center Q.
now QB for example is sqrt (25 + 12.25) = sqrt (37.25) = 6.10
call the top T
QT = 11 so the side of the triangle at the corner, TB = sqrt(11^2 + 37.25)
so TB = 12.6

Answer 2

I need explicit answer of the question