Question
A stone of mass 5kg is thrown to a height of 100m.What is the kinetic energy and it potential energy at maximum height
Answers
DrBob222
KE at maximum is zero.
PE = mgh
PE = mgh
oobleck
If it was thrown at an angle θ, then at max height
KE = mgh(1/sinθ - 1)
KE = mgh(1/sinθ - 1)
DrBob222
It never occurred to me any angle other than straight up. Got blinders on I guess. But if straight up then angle is 90 and sin 90 is 1 so KE = 0 if I did that right.
Man Stevo (eskay 77)
Assuming it was thrown upward.
At the maximum height, the velocity of the stone becomes zero and zero is substituted into the formula (1/2mv2) thus; half *mass(m)*(velocity squared)
At the maximum height, the velocity of the stone becomes zero and zero is substituted into the formula (1/2mv2) thus; half *mass(m)*(velocity squared)