KE at maximum is zero.
PE = mgh
A stone of mass 5kg is thrown to a height of 100m.What is the kinetic energy and it potential energy at maximum height
4 answers
If it was thrown at an angle θ, then at max height
KE = mgh(1/sinθ - 1)
KE = mgh(1/sinθ - 1)
It never occurred to me any angle other than straight up. Got blinders on I guess. But if straight up then angle is 90 and sin 90 is 1 so KE = 0 if I did that right.
Assuming it was thrown upward.
At the maximum height, the velocity of the stone becomes zero and zero is substituted into the formula (1/2mv2) thus; half *mass(m)*(velocity squared)
At the maximum height, the velocity of the stone becomes zero and zero is substituted into the formula (1/2mv2) thus; half *mass(m)*(velocity squared)
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