Question

An airplane is flying in a loop, following a circular path with a radius of 2.5 km in the vertical plane. What is the minimum speed that the airplane can maintain without being forced out of the circular path?
To make it over the top the mass times centripetal acceleration must be equal to m g
m g = m v^2/R
9.81 = v^2 / 2500 meters
v^2 = 9.81 * 2500 = 24525
v = 156.6 meters/ second

156.6m/s * (1 km / 1000 meters) * (3600 seconds / hour) = 564 km/hr

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