Asked by kenny
An airplane is flying in a loop, following a circular path with a radius of 2.5 km in the vertical plane. What is the minimum speed that the airplane can maintain without being forced out of the circular path?
Answers
Answered by
Anonymous
To make it over the top the mass times centripetal acceleration must be equal to m g
m g = m v^2/R
9.81 = v^2 / 2500 meters
v^2 = 9.81 * 2500 = 24525
v = 156.6 meters/ second
156.6m/s * (1 km / 1000 meters) * (3600 seconds / hour) = 564 km/hr
m g = m v^2/R
9.81 = v^2 / 2500 meters
v^2 = 9.81 * 2500 = 24525
v = 156.6 meters/ second
156.6m/s * (1 km / 1000 meters) * (3600 seconds / hour) = 564 km/hr
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