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At STP, how many liters of H2 can be made from the complete reaction of 12.5 grams of Al? (Only enter the number, NO UNITS, and round to the tenth place, 1 decimal)
Given: 2 Al + 6 HCl → 2 AlCl3. + 3 H2
Given: 2 Al + 6 HCl → 2 AlCl3. + 3 H2
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Anonymous
Al is about 27 grams per mol
so we have 12.5 grams * 1 mol / 27 grams = 0.463 mols of Al
for every 2 mols of Al you get 3 mols of H2
so mols of H2 = (3/2) * 0.463 = 0.694 mols H2
at STP as I recall 22.4 liters holds a mol
0.694 mols * 22.4 liters / mol =15.6 liters
so we have 12.5 grams * 1 mol / 27 grams = 0.463 mols of Al
for every 2 mols of Al you get 3 mols of H2
so mols of H2 = (3/2) * 0.463 = 0.694 mols H2
at STP as I recall 22.4 liters holds a mol
0.694 mols * 22.4 liters / mol =15.6 liters
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