consider the function y=(x^2+a)/(x). Find the value of the constant a so that y'(1)=.33

Answer 1

dy/dx = [ x(2x) - (x^2+a) ] / x^2
dy/dx = (x^2 - a) /x^2
when x = 1, dy/dx = .33
.33 = (1-a) / 1
a = 1 - .33