Asked by Hoz
Solve the heat combustion equation: 2N2+5O2→2N2O5 ΔH=? N2O5+H2O→2HNO3 ΔH= -76.6KJ H2+1/2O2→H2O ΔH= -285.8KJ 1/2N2+3/2O2+1/2H2→HNO3 ΔH= -174.1KJ
Answers
Answered by
DrBob222
Sorry but you didn't proof your post and the last equation didn't post correctly. I have copied it here. /2O2+1/2H2→HNO3 ΔH= -174.1KJ
My best guess is that you meant 1/2N2 + 3/2O2 + 1/2H2 = HNO3 with delta H of -174.1 kJ but I don't know that and I'm hesitant to do all that work for nothing. Please repost your program and proof it to know it is correct.
My best guess is that you meant 1/2N2 + 3/2O2 + 1/2H2 = HNO3 with delta H of -174.1 kJ but I don't know that and I'm hesitant to do all that work for nothing. Please repost your program and proof it to know it is correct.
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