Asked by JAY_ndabeh
THE HEAT OF COMBUSTION OF METHANE IS -50.38 KJ /MOL . HOW MANY MOLES OF METHANE MUST BE BURNT IN ORDER TO PRODUCE 137KJ
MM[METHANE]=16.04NG/MOL
MM[METHANE]=16.04NG/MOL
Answers
Answered by
DrBob222
You get 50.38 kJ from 1 mol CH4 so you will need
1 mol x 137/50.38 = ? mols CH4 needed.
If you want to convert to grams, but that isn't the question, grams CH4 = mols CH4 x molar mass CH4 = ?
1 mol x 137/50.38 = ? mols CH4 needed.
If you want to convert to grams, but that isn't the question, grams CH4 = mols CH4 x molar mass CH4 = ?
Answered by
JAY_ndabeh
so why don't you put the negative in your answer @DrBob222
There are no AI answers yet. The ability to request AI answers is coming soon!