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Asked by RacePlayer

Troy had 1/4 as many blocks as Doug. When Doug gave half of his blocks to Troy, he then had 5 fewer blocks than his friend. How many blocks did Doug have at first?
4 years ago

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Answered by PsyDAG
D = 4T

D/2 = 4T/2 = T + 5

Solve for T, then D
4 years ago
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Troy had 1/4 as many blocks as Doug. When Doug gave half of his blocks to Troy, he then had 5 fewer blocks than his friend. How many blocks did Doug have at first?

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