Asked by Rose ann

If the expressed mass of AlCl³ to be formed is 3.5 g, what should be the initial mass of the pure aluminum metal
Answered by R_scott
molar mass of AlCl₃ is 133 g

molar mass of Al is 27 g

3.5 g * (27 / 133) = ?
Answered by Anonymous
what is the answer?
Answered by Joy
0.71 g Al
Answered by [email protected]
Thank you
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